Question

Calculate the specific heat in J/g degrees celsius for a 24.7 g sample heated from 25.5 degrees celsius to 76.1 degrees celsius and absorbs 404 J

Answer 1

The specific heat of a 24.7 g sample heated from 25.5°C to 76.1°C while absorbing 404 J is 0.323 J/g°C.

Step-by-step explanation:

To calculate the specific heat in J/g°C for a 24.7 g sample that is heated from 25.5°C to 76.1°C and absorbs 404 J, we use the formula:

specific heat (c) = heat energy absorbed (q) / (mass (m) × change in temperature (ΔT))

First, we find the change in temperature:

ΔT = final temperature - initial temperature = 76.1°C - 25.5°C = 50.6°C

Then we calculate the specific heat:

c = 404 J / (24.7 g × 50.6°C) = 404 J / (1249.42 g°C)

c = 0.323 J/g°C

Therefore, the specific heat of the sample is 0.323 J/g°C.