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Two capacitors, 2.0 microfarads and 4.0 microfarads, are connected in parallel across a 3.00 volts potential difference. Calculate the energy stored in the capacitors.

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Final answer:

To calculate the energy stored in the capacitors, use the formula Energy = 0.5 * C * V^2. For the 2.0 microfarad capacitor with a potential difference of 3.00 volts, the energy is 9.0 x 10^-6 J. For the 4.0 microfarad capacitor with a potential difference of 3.00 volts, the energy is 36.0 x 10^-6 J. The total energy stored in the capacitors is 45.0 x 10^-6 J.

Step-by-step explanation:

To calculate the energy stored in the capacitors, we can use the formula:

Energy = 0.5 * C * V^2

Where C is the capacitance and V is the potential difference.

For the 2.0 microfarad capacitor:

  • C = 2.0 x 10^-6 F
  • V = 3.00 V

Plugging these values into the formula we get:

Energy = 0.5 * (2.0 x 10^-6 F) * (3.00 V)^2

Calculating this gives us:

Energy = 9.0 x 10^-6 J

For the 4.0 microfarad capacitor:

  • C = 4.0 x 10^-6 F
  • V = 3.00 V

Plugging these values into the formula we get:

Energy = 0.5 * (4.0 x 10^-6 F) * (3.00 V)^2

Calculating this gives us:

Energy = 36.0 x 10^-6 J

The total energy stored in the capacitors is the sum of these two values:

Total Energy = 9.0 x 10^-6 J + 36.0 x 10^-6 J

Calculating this gives us:

Total Energy = 45.0 x 10^-6 J

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