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One type of dog treat, Barker, contains 3 oz and sells for $1.95. DogYum contains 3.25 and sells for $2.10.Which is less expensive, per ounce?A. DogYum is less expensive, per ounceB. Barker is less expensive, per ounce

One type of dog treat, Barker, contains 3 oz and sells for $1.95. DogYum contains-example-1
User Juanpethes
by
2.9k points

1 Answer

24 votes
24 votes

Solution

- We are told that dog treats, Barker and DogYum cost $1.95 for 3 oz and $2.10 for 3.25 oz respectively and we are required to find out which is more expensive per ounce.

- In order to find the more expensive dog treat, we need to find the cost per ounce for each item. The cost per ounce is given by the formula below:


\frac{\text{Cost of dog treat (In Dollars)}}{\text{Weight of dog treat (In Oz)}}

- The dog treat with the larger cost per oz is the more expensive item.

- Thus, let us calculate the cost per oz for both items.

DogYum:


\begin{gathered} \frac{\text{Cost of DogYum}}{\text{Weight of DogYum}}=(2.10)/(3.25)=0.646 \\ \\ \text{Thus, the cost per oz of the DogYum treat is \$0.646/oz} \end{gathered}

Barker:


\begin{gathered} \frac{\text{ Cost of Barker}}{\text{Weight of Barker}}=(1.95)/(3)=0.65 \\ \\ \text{Thus, the cost per oz of the Barker treat is \$0.65/oz} \end{gathered}

- We can observe that Barker is marginally more expensive than DogYum. We can confirm this by simply subtracting the cost per oz for both treats.


\text{Barker - DogYum}=0.65-0.646=0.004

Final Answer

The answer is:

DogYum is less expensive, per ounce

User Cookandy
by
3.0k points
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