Question

Two particles are separated by 0.38 m and have charges of 6.25 x 10^-9 C and 2.91 x 10 C. Use Coulomb's law to predict the force between the particles if the distance is doubled. The equation for Coulomb's law is F = k * |q1 * q2| / r^2, and the constant k equals 9.00 x 10^9 Nm^2/C^2.

- A. 1.13 x 10^76 N
- B. 1.13 x 10^-6 N
- C. 2.83 x 10^-7 N
- D. 283 x 10^7 N

Answer 1

Using Coulomb's law, with the distance between the particles doubled, the new force calculated is 1.13 x 10^-6 N, which corresponds to option B.

Step-by-step explanation:

To calculate the force between two charged particles when the distance is doubled using Coulomb's law, we apply the formula F = k * |q1 * q2| / r^2, where k is the Coulomb's constant (9.00 x 10^9 Nm^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between them.

If the distance between the particles is doubled, from 0.38 m to 0.76 m, the new force can be calculated by modifying the distance variable in the denominator of the equation. The charges are 6.25 x 10^-9 C and 2.91 x 10^-9 C, and when plugged into the formula:

F = (9.00 x 10^9 Nm^2/C^2) * (6.25 x 10^-9 C * 2.91 x 10^-9 C) / (0.76 m)^2

Performing the calculation, we find the new force to be 1.13 x 10^-6 N. Hence, the correct answer is B. 1.13 x 10^-6 N.