Question

Balance the following chemical equation using algebraic method ( A value is 2 ) ( please include procedure ) Sn (NO2)4 + Pt3N4 = Sn3N4 + Pt(NO2)4

Answer 1

Answer: 3Sn (NO2)4 + Pt3N4 → Sn3N4 + 3Pt(NO2)4

Given the equation:

• Sn (NO2)4 + Pt3N4 → Sn3N4 + Pt(NO2)4

(1) The first thing we noticed is that this is a double replacement equation

• ,Sn combines with N4 to form Sn3N4, (,take note that Sn→ Sn3,)

• Pt3 combines with (NO2) to form Pt(NO2)4 ( ,take note that Pt3 → Pt)

(2) Balancing the equation

• Sn (NO2)4 + Pt3N4 → Sn3N4 + Pt(NO2)4 ....(,place 3 infront of Sn in the reactant side .)

• 3,Sn (NO2)4 + Pt3N4 → Sn3N4 + Pt(NO2)4...( ,then place 3 infront of Pt in the product side,)

,

• 3,Sn (NO2)4 + Pt3N4 → Sn3N4 + ,3,Pt(NO2)4

Check :

3Sn reactant : Sn3 Product

(NO2)4 reactant : (NO2)4 product

Pt3 reactant : 3Pt product

N4 reactant : N4 product

RHS = LHS ,this means that our equation has now balance.