Question

How many grams of copper (II) sulfate pentahydrate (CuSO4·5H2O) are required to prepare a 0.35 M solution of CuSO4 in 25.00 mL using pure, solid CuSO4·5H2O?

Answer 1

To prepare a 0.35M solution of CuSO4, you will need 2.18 grams of CuSO4·5H2O

Step-by-step explanation:

To prepare a 0.35M solution of CuSO4, we need to determine the mass of CuSO4·5H2O required. The molar mass of CuSO4 is 159.61 g/mol and the molar mass of CuSO4·5H2O is 249.69 g/mol. We can use the following formula to calculate the mass:

Mass = Moles x Molar mass

Moles = concentration x volume = 0.35 M x 25.00 mL / 1000 = 0.00875 mol

Mass = 0.00875 mol x 249.69 g/mol = 2.18 grams of CuSO4·5H2O