Question

0/1 pt 1021 0If 5.47 mol of krypton gas occupies 186.5 L, what volume would 14.1 mol of krypton occupy at the sametemperature and pressure?Use the correct number of significant figures in your answer.Question 5Submit Question Jump to Answer

Answer 1

The new volume is 480.75L.

Step-by-step explanation:

The given information from the exercise is:

- Initial amount of moles (n1): 5.47 moles

- Initial volume (V1): 186.5L

- Final amount of moles (n2): 14.1 moles

1st) We have to replace the values of V1 and n1 in the Idea Gases formula:

`\begin{gathered} P*V_1=n_1*R*T \\ P*186.5L=5.47moles*0.082(atm*L)/(mol*K)*T \\ (186.5L)/(5.47moles*0.082(atm*L)/(mol*K))=(T)/(P) \\ 415.8(K)/(atm)=(T)/(P) \end{gathered}`

Now we have a value for the relation T/P that remains constant.

2nd) Finally, we have to replace the value of the relation T/P and the amoun of moles n2:

`\begin{gathered} P*V=n_2*R*T \\ P*V=14.1moles*0.082(atm*L)/(mol*K)*T \\ V=14.1moles*0.082(atm*L)/(mol*K)*(T)/(P) \\ V=14.1moles*0.082(atmL)/(molK)*415.8(K)/(atm) \\ V=480.75L \end{gathered}`

So, the new volume is 480.75L (rounded to 481L).