Question

A girl throws a ball vertically into the air with an initial velocity of 5.4m-s Assuming air resistance is negligible, what is the maximum height reached by the ball above the girl's hand? Take acceleration due to gravity, g, to be 9.81 ms? Give your answer with an appropriate unit and to two significant figures.

Answer 1

The maximum height reached by the ball is 1.5 meters.

Step-by-step explanation:

To find the maximum height reached by the ball, we can use the equations of motion. When the ball reaches its maximum height, its vertical velocity becomes zero. We can use the equation v_f = v_i + gt, where v_f is the final velocity (zero in this case), v_i is the initial velocity (5.4 m/s), g is the acceleration due to gravity (-9.81 m/s^2), and t is the time. Rearranging the equation, we get t = -v_i/g. Substituting the values, we find t = -5.4 m/s / -9.81 m/s^2 = 0.55 s.

Now, we can use the equation h = v_i * t + (1/2) * g * t^2 to find the maximum height, where h is the height. Substituting the values, we get h = 5.4 m/s * 0.55 s + (1/2) * -9.81 m/s^2 * (0.55 s)^2 = 1.5 m. Therefore, the maximum height reached by the ball is 1.5 meters.