Final answer:
To calculate the volume occupied by a 6 mole sample of gaseous sulfur dioxide at 0°C and 760 mmHg, we can use the ideal gas law equation PV = nRT. By substituting the given values into the equation and solving for V, we find that the volume is 13.93 L.
Step-by-step explanation:
To calculate the volume occupied by a 6 mole sample of gaseous sulfur dioxide at 0°C and 760 mmHg, we can use the ideal gas law equation: PV = nRT. Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
First, we need to convert the temperature from Celsius to Kelvin by adding 273.15 K to 0°C, giving us 273.15 K. Next, we substitute the known values into the equation: 760 mmHg (pressure) x V (volume) = 6 mol (number of moles) x 0.0821 L·atm/mol·K (ideal gas constant) x 273.15 K (temperature).
Simplifying the equation, we get V = (6 mol x 0.0821 L·atm/mol·K x 273.15 K) / 760 mmHg = 13.93 L.