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Bruno has seven more dolllar bills than quarters. His money totals $3.25. How many of each does he have?

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Final answer:

Bruno cannot have any quarters and dollar bills.

Step-by-step explanation:

Let's represent the number of quarters Bruno has as x. Since Bruno has seven more dollar bills than quarters, we can represent the number of dollar bills as x + 7.

The value of quarters is 0.25x and the value of dollar bills is 1(x + 7). Since the total money is $3.25, we can write the equation:

0.25x + 1(x + 7) = 3.25

To solve this equation, we simplify:

0.25x + x + 7 = 3.25

Combining like terms, we get:

1.25x + 7 = 3.25

Subtracting 7 from both sides of the equation, we get:

1.25x = -3.75

Dividing both sides of the equation by 1.25, we get:

x = -3

Since it doesn't make sense to have a negative number of quarters, there is no solution to the problem. Therefore, Bruno cannot have any quarters and dollar bills.

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