Final answer:
To find the grams of potassium sulfate in 1.38x10^24, we need to multiply the given quantity by the molar mass of K₂SO4.
Step-by-step explanation:
The question asks how many grams of potassium sulfate are present in 1.38x10^24? In order to answer this, we need to know the molar mass of potassium sulfate. The molar mass of K₂SO4 is 39.1 + 2×(32.1) + 4×(16.0) = 174.3 g/mol. To find the grams of potassium sulfate, we can multiply the given quantity (1.38x10^24) by the molar mass:
Grams of potassium sulfate = (Moles of potassium sulfate) × (Molar mass of potassium sulfate)
Grams of potassium sulfate = (1.38x10^24) × (174.3 g/mol)
Calculating this product will give us the answer.