Final answer:
When resistors are connected in parallel, the total current supplied to the resistors is divided between them according to their resistances. For the given resistors, the current flowing through the 2-ko resistor is 20 mA and the current flowing through the 6-kQ resistor is 60 mA.
Step-by-step explanation:
When resistors are connected in parallel, the total current supplied to the resistors is divided between them according to their resistances. To find the current flowing through each resistor, we can use the current divider rule. In this case, we have a 6-kiloohm (kQ) and a 2-kiloohm (ko) resistor connected in parallel, with a total current of 80 milliamperes (mA).
To determine the current flowing through each resistor, we can use the following formula:
Ir1 = (R2 / (R1 + R2)) * Itotal
Ir2 = (R1 / (R1 + R2)) * Itotal
Plugging in the given values, we get:
Ir1 = (2 / (6 + 2)) * 80 mA = 20 mA
Ir2 = (6 / (6 + 2)) * 80 mA = 60 mA
Therefore, the current flow through each resistor would be 20 mA for the 2-ko resistor and 60 mA for the 6-kQ resistor. So the correct answer is A) 60 mA and 20 mA.