A) D = [-8, 5) U [-4, -1) U (-1, 3] U (3, 5) U [6,8]
B) R =(-7,-5) U (-4,5] U [6, 7]
C)
i. f(0) = 1
ii. f(-2) = 1
iii. f(8) = 7
iv. f(3) = 4
D.
x= 1,
x= -2
x= -4
x = -7.7 (approximately)
A) Examining the graph, we can write the Domain (the set of entries) as:
D = [-8, 5) U [-4, -1) U (-1, 3] U (3, 5) U [6,8]
Note that as we're dealing with the Real Set there are infinite values within each interval. And the Domain is the union of all intervals.
B) Examining that, for the Range (Outputs) y-axis, we can write the following:
R =(-7,-5) U (-4,5] U [6, 7]
Note that as there are some discontinuities we can't write them as a unique interval.
C) For this item, let's find out each value by locating the y-coordinate on the graph when the value of x is within the parentheses:
i. f(0) = 1 When x = 0, y = 1
ii. f(-2) = 1
iii. f(8) = 7
iv. f(3) = 4
Note that for this value, we have an open dot for -5 so it does not include it
v. f(-1) = Undefined
Both open dots
D. When f(x) = 1, i.e. y= 1 we have the following x-coordinates:
x= 1,
x= -2
x= -4
x = -7.7 (approximately)