Question

A gas has the density of 1.4 g/l when the pressure is 1 the density of the gas when the pressure is 640 mm hg at the same temperature

Option 1: 896 g/l
Option 2: 0.0021875 g/l
Option 3: 0.0000015625 g/l
Option 4: 0.00000001 g/l

Answer 1

To find the density of the gas when the pressure is 640 mmHg, we can use the ideal gas law equation. Using the given initial density of the gas, we can calculate the initial mass and then find the final density using the final volume and initial mass. The final density of the gas when the pressure is 640 mmHg is 896 g/L.

Step-by-step explanation:

To find the density of the gas when the pressure is 640 mmHg, we can use the ideal gas law equation:

PV = nRT

Since the temperature and number of moles are constant, we can rewrite the equation as:

P1V1 = P2V2

where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

In this case, the initial pressure is 1 atm and the final pressure is 640 mmHg. We need to convert 640 mmHg to atm:

1 atm = 760 mmHg

So, 640 mmHg is equal to (640/760) atm. Now we can solve for the final volume:

(1 atm)(V1) = [(640/760) atm](V2)

V2 = (1 atm)(V1) / [(640/760) atm]

Finally, we can calculate the final density using the formula:

Density = mass / volume

Since we are given the initial density of the gas (1.4 g/L), we can use it to calculate the initial mass. Then, we can use the final volume and initial mass to find the final density. So the answer is option 1: 896 g/L.