Final answer:
The number of different combinations for the combination lock with 40 numbers is obtained by multiplying the possible options for each selection: 40 choices for the first, 39 for the second, and 38 for the third. This results in 59,280 unique combinations, not matching any of the options provided.
Step-by-step explanation:
To determine the number of different combinations for a combination lock with 40 numbers, where one has to select three different numbers in sequence (right-left-right), the calculation is not factorial like 4!, but combinatorial. Since the order in which the numbers are chosen matters and each number can only be used once for each entry, the total number of combinations is the product of the number of choices for each step.
There are 40 options for the first number, 39 remaining options for the second number (since you cannot repeat the first number), and 38 options remaining for the third number. Multiply these together to get the total number of different combinations:
40 (first number) × 39 (second number) × 38 (third number) = 59,280
Therefore, none of the given options are correct; the actual number of different combinations for the lock is 59,280. If we were to choose one of the options hoping it's a typo, then the closest incorrect option given is Option 2: 64,000. The factorial method mentioned in the reference (4!) is incorrect for this problem as it is used for counting permutations without replacement in a set of 4 items, not for a sequence of different choices from 40 options.