Final answer:
The mass of water that can be vaporized with 550 kJ of energy is approximately 243.6 g, as calculated using the latent heat of vaporization of water (2256 kJ/kg). However, this answer does not match any of the provided choices, indicating a possible error in the question options.
Step-by-step explanation:
The mass of water that can be vaporized with 550 kJ of energy can be calculated using the latent heat of vaporization of water. The latent heat of vaporization for water is 2256 kJ/kg. Therefore, to find the mass (m) that can be vaporized, we use the formula:
Q = mLv
Here, Q is the energy in kilojoules and Lv is the latent heat of vaporization. Rearranging the formula to solve for m gives us:
m = Q / Lv
Substituting the given values into the equation:
m = 550 kJ / 2256 kJ/kg = 0.2436 kg
Since 1 kg is equal to 1000 g, we convert 0.2436 kg to grams:
m = 0.2436 kg × 1000 g/kg = 243.6 g
Thus, the mass of water that can be vaporized with 550 kJ of energy is approximately 243.6 g, which is not an option listed in the question. It seems there may be an error in the question as none of the answer choices match the correct calculation based on the latent heat of the vaporization of water.