Question

I have attached an image with all of the information.

Answer 1

Step-by-step explanation:

For reactants: BE 2CH2OH = 2*(3*414+351+460) = 4106kJ/mol

: BE 3O2 = 3*499 = 1497kJ/mol

For products: BE 2CO2 = 2*799 = 1598kJ/mol

: BE 4H2O = 4*2*460 = 3680kJ/mol

`\begin{gathered} BE\text{ = Sum}_(reactants)\text{ - Sum}_(products) \\ \\ \text{ = 4106+1497-\lparen1598+3680\rparen} \\ \\ \text{ = 325kJ/mol} \end{gathered}`

Answer:

Bond energy is 325kJ/mol