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The sum of two numbers is 58. Twice the second

number subtracted to four times the first number is
28. Find the two numbers.Write the system of equations
a. (15, 43)
b. (20, 38)
c. (24, 34)
d. (36, 12)

1 Answer

5 votes

Final answer:

The two numbers that satisfy the given conditions are 24 and 34. A system of equations was set up and solved using substitution to find the figures.

Step-by-step explanation:

To find the two numbers, we need to set up a system of equations based on the information given. The sum of two numbers is 58, so we have:

Equation 1: x + y = 58

Twice the second number subtracted from four times the first number is 28, which gives us:

Equation 2: 4x - 2y = 28

We can now solve this system of equations by using the substitution or elimination method. Let's use the substitution method by solving equation 1 for y:

y = 58 - x

Next, we substitute the expression for y into equation 2:

4x - 2(58 - x) = 28

Expanding and simplifying gives us:

4x - 116 + 2x = 28

6x = 144

x = 24

Now, we substitute x back into equation 1 to find y:

24 + y = 58

y = 34

Therefore, the two numbers are 24 and 34.

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