Question

Laureen is placing appetizers on plates. She has 81 chicken fingers and 63 cups of mac and cheese. She wants to have both appetizers on each plate. Each plate must have the same number of chicken fingers and cups of mac and cheese. What is the greatest number of plates she can make using all the appetizers. How many of each type of appetizer will be on each plate?

Answer 1

Laureen can make 9 plates each with 9 chicken fingers and 7 cups of mac and cheese by finding the greatest common divisor (GCD) of the quantities of the appetizers she has.

Step-by-step explanation:

The question revolves around finding the greatest number of plates Laureen can make with 81 chicken fingers and 63 cups of mac and cheese such that each plate has an equal number of each appetizer. This is a classic example of a problem that requires finding the greatest common divisor (GCD) or highest common factor (HCF) to determine the maximum number of plates that can be made without any leftovers.

To solve this, we first need to find the GCD of 81 and 63. The GCD of these two numbers is 9, meaning we can make 9 plates with an equal number of chicken fingers and cups of mac and cheese without any leftovers.

Dividing both 81 chicken fingers and 63 cups of mac and cheese by the GCD, we determine the amount of each appetizer per plate:

• 81 chicken fingers ÷ 9 plates = 9 chicken fingers per plate
• 63 cups of mac and cheese ÷ 9 plates = 7 cups of mac and cheese per plate

Thus, Laureen can make 9 plates with 9 chicken fingers and 7 cups of mac and cheese on each plate.