Final answer:
There are three possible isomers of C₄H₉Br, with different positions of the bromine atoms on a six-carbon ring structure.
Step-by-step explanation:
One way to draw the isomers of C₄H₉Br using bond-line formulas is to start with a six-carbon ring structure, such as benzene, and replace two of the hydrogen atoms with bromine atoms. There are three possible isomers:
1. The first isomer has the two bromine substitutions adjacent to each other.
2. The second isomer has the two bromine atoms separated by one carbon.
3. The third isomer has the two bromine atoms separated by two carbons.