Final answer:
The amount of phosphoric acid produced in the given reaction is 98 grams. We calculate this by first finding the molar mass of phosphoric acid and then using the 1:1 stoichiometric ratio offered by the balanced equation. Option b is correct.
Step-by-step explanation:
The calculation of the mass of phosphoric acid produced from the given chemical reaction requires the use of stoichiometry.
First, we must calculate the molar mass of phosphoric acid (H3PO4).
To do this, we need to add the atomic masses of each element in the compound, which are as follows:
- Hydrogen (H): 1.01 g/mol × 3 = 3.03 g/mol
- Phosphorus (P): 30.97 g/mol
- Oxygen (O): 16.00 g/mol × 4 = 64.00 g/mol
The molar mass of H3PO4 is the sum of these masses: 3.03 g/mol + 30.97 g/mol + 64.00 g/mol
= 98.00 g/mol.
In the balanced chemical equation provided:
K3PO4 + 3HCl → 3KCl + H3PO4,
it shows that 1 mole of K3PO4 yields 1 mole of H3PO4.
Therefore, if one mole of K3PO4 is used, 98 g of H3PO4 would be produced, since the ratio of K3PO4 to H3PO4 is 1:1 in the equation.
Therefore, the correct answer is B) 98 g.