Final answer:
After evaluating the expressions '4 + 2v' and 'v^2' for v = 3 and v = 6, it is clear that the expressions are not equivalent and the values for the given instances of v do not match any of the provided statements, confirming that option (f) is correct.
Step-by-step explanation:
First, we need to clarify the original expressions to evaluate. There seems to be a typo in the question, as the expressions provided "4 + 2(1) = 4 and 1" do not contain the variable v. I will assume that the expressions meant are "4 + 2v" and "v^2", which commonly appear in algebraic problems. Let's check if these expressions are equivalent and what their values are when v = 3 and v = 6.
When v = 3:
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- The expression 4 + 2v becomes 4 + 2(3) which is 4 + 6 = 10.
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- The expression v^2 becomes (3)^2 which is 9.
When v = 6:
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- Using 4 + 2v, we get 4 + 2(6) which is 4 + 12 = 16.
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- And v^2 as (6)^2 gives us 36.
Based on our calculations:
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- (a) is incorrect because both expressions do not equal 13 when v = 3.
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- (b) is incorrect as neither expression equals 22 for v = 3.
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- (c) is incorrect because the expressions do not equal 23 when v = 6.
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- (d) does not apply as no value for v of 1 was used in the question.
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- (e) is incorrect because the expressions 4 + 2v and v^2 are not equivalent, as shown by their different values for v = 3 and v = 6.
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- (f) is correct since the expressions are not equivalent.