Question

If the initial volume of a gas at 129.9°C is 2.852 L, what would be the volume of the gas at -25.46°C?

a) 2.427 L
b) 3.100 L
c) 2.852 L
d) 2.215 L

Answer 1

To find the volume of a gas at a different temperature, you can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature. Using the formula V1/T1 = V2/T2, you can solve for the final volume (V2) when given the initial volume and temperature (V1 and T1) and the final temperature (T2). Using this formula, the volume of the gas at -25.46°C is approximately 2.427 L.

Step-by-step explanation:

To find the volume of the gas at -25.46°C, we can use Charles's Law. Charles's Law states that the volume of a gas is directly proportional to its temperature, assuming pressure and amount of gas are held constant.

In this case, the initial volume is 2.852 L at 129.9°C. To find the volume at -25.46°C, we can use the formula V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

Plugging in the values, we get (2.852 L)/(129.9°C + 273.15) = V2/(-25.46°C + 273.15). Solving for V2, we find that the volume of the gas at -25.46°C is approximately 2.427 L.