Final answer:
To find the percent yield, you need to compare the actual yield of carbon monoxide to the theoretical yield of oxygen. Use stoichiometry to calculate the moles of CO and O2, and then convert to grams. Divide the actual yield by the theoretical yield and multiply by 100 to get the percent yield.
Step-by-step explanation:
To find the percent yield, you need to compare the actual yield (0.0522 g of carbon monoxide) to the theoretical yield. Theoretical yield is the maximum amount of product that can be formed based on the balanced chemical equation and the limiting reactant. In this case, oxygen is the limiting reactant. Calculate the moles of CO produced from the given mass of CO, and then use stoichiometry to determine the moles of oxygen required to produce that amount of CO. Finally, use the molar mass of oxygen to convert the moles to grams. Divide the actual yield by the theoretical yield and multiply by 100 to get the percent yield.
Using the molar mass of carbon monoxide (28.01 g/mol), the moles of carbon monoxide produced can be calculated as:
0.0522 g CO * (1 mol CO/28.01 g CO) = 0.00186 mol CO
From the balanced equation C + O2 → CO2, we know that 1 mole of CO2 is produced for every 2 moles of CO (stoichiometry). Therefore, the moles of oxygen required to produce 0.00186 mol of CO is:
0.00186 mol CO * (1 mol O2/2 mol CO) = 0.00093 mol O2
Lastly, use the molar mass of oxygen (32.00 g/mol) to calculate the theoretical yield in grams:
0.00093 mol O2 * (32.00 g O2/1 mol O2) = 0.02976 g O2
Now calculate the percent yield:
Percent yield = (0.0522 g CO / 0.02976 g O2) * 100 = 175.3%