Final answer:
The amount of heat required to evaporate 250 g of water to the boiling point is 562.5 kJ. This process is endothermic.
Step-by-step explanation:
The amount of heat required to evaporate 250 g of water to the boiling point can be calculated using the formula: Q = mLv, where Q is the heat required, m is the mass of water, and Lv is the latent heat of vaporization. The latent heat of vaporization of water is approximately 2250 J/g. Therefore, the heat required = (250 g) * (2250 J/g) = 562,500 J. To convert this to kJ, divide by 1000: 562,500 J = 562.5 kJ.
Since heat is being added to the water to evaporate it, this process is endothermic. Therefore, the correct answer is A. 250 kJ, endothermic.