Question

A ball falls from the ground into a pit that is 2.5 feet deep, and then bounces to a height of 2.5 feet above ground. What is the net displacement of the ball during this process?

Answer 1

The net displacement of the ball that falls into a pit and bounces back up is 0 feet, as the ball ends up at the same level from where it fell.

Step-by-step explanation:

The question asks about the net displacement of a ball that falls into a pit and then bounces back up above ground. To calculate the net displacement, we consider the total distance traveled in one direction and subtract the distance traveled in the opposite direction. The ball falls 2.5 feet down into the pit, and then bounces back up 2.5 feet above ground. The displacement when falling down is -2.5 feet (negative because it is downward), and the displacement when bouncing up is +2.5 feet (positive because it is upward).

So, the net displacement is:
Net Displacement = Displacement down + Displacement up
Net Displacement = -2.5 feet + 2.5 feet
Net Displacement = 0 feet

The net displacement of the ball is 0 feet since it ends up at the same level from where it initially fell.