Question

Write the equation of the line that has a slope of -2 that contains the point (-3,5). Just write in the slope and y-intercept.

A. y = -2x + 11
B. y = -2x - 1
C. y = -2x + 5
D. y = -2x + 9

Answer 1

To find the equation of a line with a given slope and a point on the line, we can use the point-slope form of the equation.

Step-by-step explanation:

To find the equation of a line with a given slope and a point on the line, we can use the point-slope form of the equation:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is the given point. In this case, the slope is -2 and the point is (-3, 5). Plugging these values into the equation, we get:

y - 5 = -2(x - (-3))

Simplifying this equation gives us:

y - 5 = -2(x + 3)

which can be further simplified to:

y - 5 = -2x - 6

Adding 5 to both sides of the equation:

y = -2x - 1

Therefore, the equation of the line with a slope of -2 that contains the point (-3, 5) is y = -2x - 1.