Final answer:
After testing each option by substituting the x and y values in the line equation 3x+5y=30, the only point that lies on the line is B) (10,0).
Step-by-step explanation:
The student is asked to identify which points are on the graph of the line given by the equation 3x+5y=30. To determine if a point lies on the line, we substitute the x and y values of the point into the equation and see if the equation holds true. Let's test each option.
- A) (1,5): Substituting x = 1 and y = 5 into the equation: 3(1) + 5(5) = 3 + 25 = 28, which does not equal 30, so (1,5) is not on the line.
- B) (10,0): Substituting x = 10 and y = 0 into the equation: 3(10) + 5(0) = 30 + 0 = 30, which equals 30, so (10,0) is on the line.
- C) (20,10): Substituting x = 20 and y = 10 into the equation: 3(20) + 5(10) = 60 + 50 = 110, which does not equal 30, so (20,10) is not on the line.
- D) (15,8): Substituting x = 15 and y = 8 into the equation: 3(15) + 5(8) = 45 + 40 = 85, which does not equal 30, so (15,8) is not on the line.
Therefore, the only point that lies on the line is B) (10,0).