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If an object is dropped, the distance it fails during t seconds is given by d(t)=1/2gt^2, where g is about 32ft/sec^2. Find the distance an object would fall in 8 seconds.

If an object is dropped, the distance it fails during t seconds is given by d(t)=1/2gt-example-1
User Gpuser
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1 Answer

18 votes
18 votes

Since the distanc function is given by


d(t)=(1)/(2)gt^2

in order to find the distance at 8 seconds, we need to substitute t=8 into this function, that is,


d(8)=(1)/(2)g(8)^2

By taking into account that g=32 ft/sec^2, we have


d(8)=(1)/(2)(32)(64)

which gives


\begin{gathered} d(8)=16*64 \\ d(8)=1024 \end{gathered}

Therefore, the answer is 1024 ft, which corresponds to the last option.

User Chris Mungall
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