Question

A car travels 80 meters due north in 12 seconds. Then the car turns around and travels 60 meters due south in 7 seconds. What is the magnitude of the average velocity of the car during this 19-second time period?

A) 0.05 m/s
B) 1.05 m/s
C) 5.05 m/s
D) 10.05 m/s

Answer 1

The magnitude of the average velocity of the car is calculated by dividing the net displacement (20 meters north) by the total time (19 seconds), resulting in 1.05 m/s.

Step-by-step explanation:

To find the magnitude of the average velocity of the car during the entire 19-second time period, we need to consider the net displacement of the car and the total time taken. First, the car travels 80 meters north and then 60 meters south, resulting in a net displacement of 20 meters to the north (80 meters - 60 meters). Since the total time taken is 19 seconds, we use the formula for average velocity, which is total displacement divided by total time.

The calculation is as follows:
Average Velocity = Net Displacement / Total Time
Average Velocity = 20 meters / 19 seconds
Average Velocity = 1.05 m/s

Therefore, the magnitude of the average velocity of the car during this 19-second time period is 1.05 m/s, which corresponds to option B.