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Please answer question attached

Please answer question attached-example-1

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Explanation:

remember the law of cosine :

c² = a² + b² - 2ab×cosC

a, b, c are the 3 sides of the triangle.

C is the opposite angle of side c.

so, this applies to all 3 sides :

a² = b² + c² - 2bc×cosA

b² = a² + c² - 2ac×cosB

a)

cos (x) : its opposite side is 3.

3² = 7² + 5² - 2×7×5×cos(x)

9 = 49 + 25 - 70×cos(x)

9 = 74 - 70×cos(x)

-65 = -70×cos(x)

cos(x) = -65/-70 = 13/14

b)

cos (z) : its opposite side is 7.

7² = 3² + 5² - 2×3×5×cos(z)

49 = 9 + 25 - 30×cos(z)

49 = 34 - 30×cos(z)

15 = -30×cos(z)

cos(z) = 15/-30 = -1/2

User Dulitha K
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