Question

1. Find the domain and range of f(x) = sqrt(x)2. Find the domain and range of f(x) = 3x + 2

Answer 1

We have the function:

`f(x)=\sqrt[]{x}`

The domain is the set of values of x for which f(x) is defined. In this case, f(x) is defined only for non-negative values of x, so the domain is D:{x≥0}.

The range is the set of values that f(x) can take for the domain in which it is defined. In this case, f(x) will only take non-negative values, so the range can be defined as R: {y≥0}.

For the linear function f(x) = 3x+2, we don't have restrictions for the domain and the the range: both x and y can take any real value, so the domain and range are D: {x: all real numbers} and R: {y: all real numbers}.

Answer:

For the function f(x) = √x, the domain is D:{x≥0} and the range is R: {y≥0}.

For the function f(x) 3x+2, the domain is D: {x: all real numbers} and the range is R: {y: all real numbers}.