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8 votes
8 votes
two trains leave town 906 miles aprt at the same time and travel each other. one train travels 21 mi/h faster than other. if they meet in 6 hours, what is the rate of each train?

User Zaboco
by
2.7k points

1 Answer

17 votes
17 votes

Let

x be the speed of the slower train

x + 21 be the speed of the faster train

They meet in 6 hours which means that their speed is


(906)/(6)=151

The sum of their therefore is


\begin{gathered} x+(x+21)=151 \\ 2x+21=151 \\ 2x=151-21 \\ 2x=130 \\ (2x)/(2)=(130)/(2) \\ x=65\frac{\operatorname{mi}}{\operatorname{h}}\text{ (speed of slower train)} \\ \\ x+21=65+21=86\frac{\operatorname{mi}}{\operatorname{h}}\text{ (speed of faster train)} \end{gathered}

User Couchy
by
3.2k points
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