Final answer:
To cover a room measuring 24'x24'x8' with drywall, one needs a total of 1,344 square feet of drywall. This includes 768 square feet for the walls and 576 square feet for the ceiling.
Step-by-step explanation:
To calculate the amount of drywall required to cover an entire room measuring 24'x24'x8', we need to calculate the surface area of all the walls and the ceiling. The floor area (24'x24') is not typically covered with drywall, so it does not need to be included.
First, find the area of one wall. Since the room is 24' wide and 8' tall, one wall's area is 24' x 8' = 192 square feet. Because the room is square, all four walls will have the same dimensions and thus the same area. So, multiply one wall's area by four to get the total wall area: 192 sq ft x 4 = 768 square feet.
Next, calculate the area of the ceiling. The room is a square, so the length and width of the ceiling are the same as the floor, which is 24'x24'. Therefore, the ceiling area is 24' x 24' = 576 square feet.
Finally, add the total wall area to the ceiling area to get the total amount of drywall needed: 768 sq ft + 576 sq ft = 1,344 square feet of drywall.