Question

Black fur (B) is dominant over brown fur (b) and short fur (F) is dominant over long fur (f). What percentage of the offspring from a bbFf x BBff cross would be expected to be heterozygous for both traits?

0%
25%
50%
100%
I'm looking for an example of these things:
The punnett square for each trait
Counted genotypes in fraction form
The genotype that matches what It's looking for
That genotypes' fractions, multiplied
Converted to a percentage

Answer 1

In a cross between bbFf and BBff, 50% of the offspring would be expected to be heterozygous for both the black fur and short fur traits.

Step-by-step explanation:

In a cross between bbFf and BBff, we can use a Punnett square to determine the genotypes and phenotypes of the offspring. For the fur color trait, black fur (B) is dominant over brown fur (b), and for the fur length trait, short fur (F) is dominant over long fur (f).

The Punnett square for the fur color trait would look like this:
Bb Bb
bb bb

The Punnett square for the fur length trait would look like this:
Ff ff
Ff ff

Combining the two Punnett squares, we get the following genotypes:
BbFf BbFf
bbFf bbFf

Out of these genotypes, 50% are heterozygous for both traits (BbFf), so the expected percentage of offspring that are heterozygous for both traits is 50%.