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5. In the circuit of figure 2.37, switch K is open. a. Show the connections to be made to an oscilloscope in order to observe, on the screen, the shape of figure 2.38. b. The vertical sensitivity of the oscilloscope is 2V/cm. What is the value of the measured potential difference? Figure 2.37. +|||||||| Figure 2.38.​

User MCB
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1 Answer

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Answer:

Potential Difference

=Vertical Distanc×Vertical Sensitivity

Potential Difference=Vertical Distance×Vertical Sensitivity

Potential Difference

=4cm*2V/cm=8V

Potential Difference=4cm×2V/cm=8V

Step-by-step explanation:

Horizontal Connection:

  • Connect the horizontal input (time/div) of the oscilloscope to a point in the circuit where you want to observe the voltage variation with time.

Vertical Connection:

  • Connect the vertical input (volts/div) of the oscilloscope to a point in the circuit where you want to observe the voltage variation with respect to another point (ground or reference).

Ground Connection:

  • Connect the ground lead of the oscilloscope to the common ground of the circuit.

Observing the Voltage Waveform:

Power On and Calibrate:

  • Power on the oscilloscope and ensure it is properly calibrated. Adjust the time/div and volts/div settings for a clear view of the waveform.

Adjust Triggering:

  • Set the triggering level and source to stabilize the waveform on the screen.

Calculating the Potential Difference:

1-Measure the Voltage:

Identify the waveform on the screen and measure its vertical distance. If the waveform is, for example, 4 cm high on the screen, and the vertical sensitivity is 2V/cm, then the potential difference is

4cm*2V/cm=8V

4cm×2V/cm=8V.

User Hali
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