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a converging lens has a focal length of 8.00 cm. if the object is 6.00 cm high, what is the height of the image for the object distance of 18.6 cm?

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Final answer:

To calculate the height of the image formed by a converging lens with a given focal length and object distance, we can use the thin lens equation and the magnification formula.

Step-by-step explanation:

To calculate the height of the image, we can use the thin lens equation: 1/f = 1/do + 1/di, where f is the focal length of the lens, do is the object distance, and di is the image distance.

We know that the focal length of the lens is 8.00 cm and the object distance is 18.6 cm. Plugging in these values, we can rearrange the equation to solve for di: 1/di = 1/f - 1/do. Substituting the values, we get 1/di = 1/8.00 - 1/18.6.

Calculating this expression gives us a value of 0.012416, which is approximately equal to 0.0124. Taking the reciprocal, we find that di = 80.65 cm.

Now, we can use the magnification formula, M = -di/do, where M is the magnification. Plugging in the values, we get M = -80.65/18.6. Calculating this expression gives us a value of -4.34, which is approximately equal to -4.3.

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