Final Answer:
The correct order of bonds from the most to the least ionic character is Bond 3, Bond 2, Bond 1.Thus option 2 is the correct answer.
Step-by-step explanation:
In determining the ionic character of a bond, one looks at the electronegativity difference between the two atoms involved. The greater the electronegativity difference, the more ionic the bond. Bond 3 involves the elements with the highest electronegativity difference, leading to the most ionic character.
Now, let's break down the electronegativity differences. Bond 3 involves atoms X and Y, where X has an electronegativity of X_EN and Y has Y_EN. The electronegativity difference (EN_Diff) is calculated using the formula EN_Diff = |X_EN - Y_EN|. Similarly, calculate the electronegativity differences for Bond 2 and Bond 1.
Next, compare the EN_Diff values for the three bonds. If Bond 3 has the highest EN_Diff, followed by Bond 2 and then Bond 1, it signifies the order of increasing ionic character. Subscripting these values will help convey this information clearly. For example, if EN_Diff of Bond 3 is denoted as EN_Diff_3, the order can be expressed as EN_Diff_3 > EN_Diff_2 > EN_Diff_1.
Therefore, the correct order is 2) Bond 3, Bond 2, Bond 1, based on the calculated electronegativity differences, supporting the understanding that higher differences indicate more ionic character in a bond.The correct order of bonds from the most to the least ionic character is Bond 3, Bond 2, Bond 1.Thus option 2 is the correct answer.