Question

substrate level phosphorylation Transfer of 1P BPG to ATP ---> (2) 3-phosphoglycerate (3C) produces 2 ATP

Answer 1

Substrate-level phosphorylation involving the transfer of 1 phosphate (P) from 1,3-bisphosphoglycerate (1,3-BPG) to ADP produces 2 molecules of ATP, resulting in the formation of 3-phosphoglycerate (3-PG).

Step-by-step explanation:

Substrate-level phosphorylation is a metabolic process where a phosphate group (P) is transferred from a substrate molecule to ADP, generating ATP directly. In this specific case, the substrate is 1,3-bisphosphoglycerate (1,3-BPG), and the phosphorylation event results in the formation of 3-phosphoglycerate (3-PG). The chemical equation for this reaction can be represented as follows:

`\[1,3-BPG + ADP \xrightarrow{\text{Substrate-level phosphorylation}} 3-PG + 2 ATP.\]`

The process involves the transfer of one phosphate group (1P) from 1,3-BPG to ADP, ultimately yielding 3-phosphoglycerate and 2 molecules of ATP. This direct generation of ATP is a crucial step in cellular energy production during glycolysis.

Understanding the intricacies of substrate-level phosphorylation is fundamental to comprehending cellular respiration and energy transfer in living organisms. Glycolysis, where this reaction occurs, is a central pathway for breaking down glucose to produce energy in the form of ATP. The step involving 1,3-BPG is particularly significant as it contributes to the net production of ATP during glycolysis, playing a pivotal role in cellular energy metabolism.

Complete Question:

What is the transfer of a phosphate group from 1,3-bisphosphoglycerate to ADP?