Final answer:
The tension force in the string pulling a block with a coefficient of kinetic friction of 0.1 is calculated by adding the force of friction to the weight of the block, resulting in a total tension of 165 N. Option a is correct.
Step-by-step explanation:
To calculate the tension force in the string pulling a 150 N block with a coefficient of kinetic friction of 0.1, we must first determine the force of friction.
The force of friction (Ffriction) is calculated by multiplying the normal force (N), which in this case is equal to the weight of the block (150 N), by the coefficient of kinetic friction (μk).
Ffriction = N × μk
= 150 N × 0.1
= 15 N
The net force (Fnet) acting on the block is the difference between the tension force (T) and the force of friction (Ffriction).
Since there's no acceleration mentioned, we can assume the block is moving at constant velocity, which means the net force is zero. Thus, the tension force must be equal to the force of friction:
T = Ffriction = 15 N
However, since we are looking for the total tension in the string and the block's weight also acts as a force on the string, we must add the weight of the block to the force of friction:
T = weight of the block + force of friction = 150 N + 15 N
= 165 N
Therefore, the tension force in the string is 165 N, which corresponds to option a. 165 N.