Final answer:
The described process with an entropy increase of 125 J/K and no energy becoming unavailable for work is reversible. The change in the entropy of the surroundings for a reversible process is equal in magnitude but opposite in sign to that of the system, resulting in -125 J/K.
Step-by-step explanation:
A student asked whether a process with an entropy increase of 125 J/K, with no energy becoming unavailable for work, is reversible or irreversible, and the change in the entropy of the surroundings.
Answer to (a):
The process described is reversible. If no energy becomes unavailable for work, it means that the energy transfer is completely efficient, which is a characteristic of a reversible process. According to the second law of thermodynamics, in any real (irreversible) process, entropy increases and some energy becomes unavailable to do work. If in this case, the energy unavailable for work is zero, this theoretical scenario would be considered reversible.
Answer to (b):
Since the process is reversible and the system has gained entropy, the surroundings must have lost an equal amount of entropy to maintain the total entropy of the isolated system (system + surroundings). Therefore, the change in the entropy of the surroundings is -125 J/K.