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A cylindrical drinking glass is 7 inches tall and has a base diameter of 3.5 inches. If 1 cubic inch of water is equal to 0.55 fluid ounces of water, how much water can the glass hold? Round the answer to the nearest hundredth of a fluid Ounce. a) 38.86 ounces b) 37.04 ounces c) 79.48 ounces d) 70.65 ounces

User TheAhmad
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Final answer:

To calculate the volume of a cylindrical glass, apply the formula V = πr^2h and then convert from cubic inches to fluid ounces using 1 cubic inch = 0.55 fluid ounces. The volume in ounces is approximately 38.4857, rounded to 38.49 ounces.

This correct answer is none of the above.

Step-by-step explanation:

To calculate the volume of water a cylindrical glass can hold, you must first find the volume of the cylinder. The formula for the volume of a cylinder is V = πr^2h, where V is volume, r is radius, and h is height.

Given that the height (h) of the glass is 7 inches and the diameter is 3.5 inches, hence the radius (r) is half of that, which is 1.75 inches. The calculation of the volume in cubic inches would therefore be π * (1.75)^2 * 7.

Now to convert cubic inches to fluid ounces, we use the given conversion factor: 1 cubic inch = 0.55 fluid ounces. So, we multiply the volume of the cylinder in cubic inches by 0.55 to convert it to fluid ounces. Finally, we round the resulting number to the nearest hundredth of a fluid ounce to get the capacity of the glass.

The final calculation is: V = π * 1.75^2 * 7 * 0.55 which approximately equals 38.4857 ounces, hence after rounding up, we get 38.49 ounces.

This correct answer is none of the above.

User Prashant Kumar
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