Question

Calculate Reactions 1, 2 and 3 using standard entropy change.
Need this asap.

Answer 1

The entropy of the redactions are;

1) -184.5 JK-1mol-1

2) -88.96 JK-1mol-1

3) 125.6 JK-1mol-1

What is the change in entropy?

Entropy is a measure of the disorder or randomness in a system. In a thermodynamic process

The change in entropy is obtained as;

Entropy of products - Entropy of reactants

Reaction 1;

[2(43.50)] - [2(33.30) + (204.90)]

87 - 271.5

= -184.5 JK-1mol-1

Reaction 2;

[2(188.70)] - [2(130.68) + (205)

377.4 - 466.36

=-88.96 JK-1mol-1

Reaction 3;

[2(69.9) + 205) - [2(109.6)]

344.8 - 219.2

= 125.6 JK-1mol-1