Question

a current in a circuit is increasing at a rate of 0.075 a/s which induces an emf of magnitude 0.024 v. what is the inductance of the circuit? if the inductor has 500 turns, what is the average magnetic flux through each turn when the current is 0.65 a?

Answer 1

The inductance of the circuit is 160 ohms and the average magnetic flux through each turn is 0.208 mWb when the current is 0.65 A.

Step-by-step explanation:

The formula for the self-inductance of a coil is given by the equation:

L = (N * Φ) / I

where L is the inductance of the coil, N is the number of turns, Φ is the average magnetic flux through each turn, and I is the current.

In this case, the inductance of the circuit can be found using the given information:

L = (500 * 0.024) / 0.075

= 160 ohms

Next, to find the average magnetic flux through each turn when the current is 0.65 A, we can rearrange the equation:

Φ = (L * I) / N

= (160 * 0.65) / 500

= 0.208 mWb/turn