51.5k views
5 votes
the heights of 12-month-old baby boys are normally distributed with the average of 76.4 cm and standard deviation of 2.9 cm. find the value which separates top 20% of the of heights of 12-mounth-old baby boys. (round your answer to 2 places after the decimal point).

User JohnFx
by
7.4k points

1 Answer

4 votes

Final answer:

To find the value which separates the top 20% of the heights of 12-month-old baby boys, we need to find the z-score corresponding to that percentile and then use it to calculate the actual height value.

Step-by-step explanation:

To find the value which separates the top 20% of the heights of 12-month-old baby boys, we need to find the z-score corresponding to that percentile and then use it to calculate the actual height value. First, we find the z-score using the formula:

z = (x - μ) / σ

where x is the height value, μ is the average height, and σ is the standard deviation. We can rearrange the formula to solve for x:

x = z * σ + μ

Next, we find the z-score that corresponds to the top 20% of the distribution. This z-score is the inverse of the cumulative distribution function (CDF) for the normal distribution.

Using a z-score table or a statistical calculator, we find that the z-score corresponding to the top 20% is approximately 0.8416.

Finally, we substitute the z-score and the given values for μ and σ into the equation to solve for x:

x = 0.8416 * 2.9 + 76.4

= 78.44

Therefore, the value that separates the top 20% of the heights of 12-month-old baby boys is approximately 78.44 cm.

User Difusio
by
8.1k points