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41 votes
I need help figuring out the answer to the m2

I need help figuring out the answer to the m2-example-1
User Luke Wage
by
2.6k points

1 Answer

11 votes
11 votes

The area of the composite figure can be solved by separating the figure into 3 portions, which are 2 identical rectangles with one rectangle.

The image of the composite figure will be shown below

Let us sketch out the image of the two identical rectangles

The formula for the area(A) of a rectangle is,


A=length* width

where,


\begin{gathered} l=length=5m \\ w=width=2m \end{gathered}

Therefore, the area(A1) of the two identical rectangles are


\begin{gathered} A_1=2*(5*2)=2*5*2=20m^2 \\ \therefore A_1=20m^2 \end{gathered}

Let me sketch the second rectangle

Therefore, the area(A2) will be


\begin{gathered} A_2=3*2=6m^2 \\ \therefore A_2=6m^2 \end{gathered}

Hence, the area(A) of the composite figure is


\begin{gathered} A=A_1+A_2=20m^2+6m^2=26m^2 \\ \therefore A=26m^2 \end{gathered}

Therefore, the area is


26m^2

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