Question

10. commercial vinegar was titrated with naoh solution to determine the content of acetic acid, hc2h3o2 for 20.0 milliliters of the vinegar 26.7 milliliters of 0.600-molar naoh solution was required. what was the concentration of acetic acid in the vinegar if no other acid was present?

Answer 1

The concentration of acetic acid in the vinegar is 0.802 M.

Step-by-step explanation:

The concentration of acetic acid in the vinegar can be determined using the titration data. From the given information, 26.7 milliliters of 0.600-molar NaOH solution was required to titrate 20.0 milliliters of the vinegar. The balanced chemical equation for the reaction between acetic acid and NaOH is:

CH3CO2H + NaOH → CH3CO2Na + H2O

By comparing the reaction stoichiometry, we can determine that the number of moles of acetic acid in the vinegar is equal to the number of moles of NaOH used in the titration. Therefore, the concentration of acetic acid can be calculated by dividing the moles of acetic acid by the volume of vinegar used in the titration:

Concentration of acetic acid = (moles of acetic acid) / (volume of vinegar)

Substituting the given values:

Concentration of acetic acid = (0.600 mol/L) × (26.7 mL / 1000 mL) / (20.0 mL / 1000 mL) = 0.802 M