Question

1.). Two planes leave Dingle City at 1 PM. Plane A heads east at 450 mph and Plane B heads due west at 600 mph. How long will it be before the planes are 2100 miles apart? (No wind) but I need to do this with the Read, plan, solve, check format.

Answer 1

We have that the functions that describes their movement are

`x=x_(0A)+v_At`

And:

`x=x_(0B)+v_Bt`

We then proceed as follows:

`x_(0A)+v_At+x_(0B)+v_Bt=2100`

Then:

`v_At+v_Bt=2100`

That since their starting positions are the same and are 0, then:

`t(v_A+v_B)=2100\Rightarrow t=(2100)/(v_A+v_B)`

We then replace the values of vA and Vb, these are the velovities of each plane:

`t=(2100)/(450+600)\Rightarrow t=2`

The time it would take them to b 2100 miles apart is 2 hours.

* We determine the function that describes the trajectory of each plane with respect to their final position and speed, then since we know their expected distance we add both expressions (Since the total of their trajectories will give us the total distance) and solve for the time.