Question

light of intensity 24 x 1018 ev/(s*m2) is incident perpendicularly on a material with an area of 1 m2. the work function of the material is 2.0 ev and the light frequency is 2 x 1015 hz.how many electrons are freed from the material in 4 seconds?

Answer 1

The number of electrons freed from the material in 4 seconds is approximately 1.16 x 10^27 electrons.

Step-by-step explanation:

To determine the number of electrons freed from the material in 4 seconds, we can use the equation:

Number of electrons = (Intensity of light x Area of material x Time)/(Energy per photon)

Given that the intensity of light is 24 x 10^18 eV/(s*m^2), the area of material is 1 m^2, the time is 4 seconds, and the energy per photon is given by E = hf = 2 x 10^15 x (4.14 x 10^-15) = 8.28 x 10^-9 eV, we can substitute these values into the equation:

Number of electrons = (24 x 10^18 x 1 x 4)/(8.28 x 10^-9) = 1.16 x 10^27 electrons