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sin(B)=(y)/(z) =(1)/(√(3) ) \ \Longrightarrow\ √(3) *y=z\\Theorem\ of\ Pythagore: x^2+y^2=z^2 \ \Longrightarrow\ 100+y^2=z^2\\\\We\ substitue\ z\ with\ its\ value\\\\100+y^2=3y^2\\\\2y^2=100\\\\y=5√(2) \\\\z=√(3) *y=5√(6)

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